At a 220/132kV Sub-Station there are two ICTs operating in parallel. ICT-I having capacity of 200 MVA.
Whereas the capacity of ICT-II is 100 MVA.
HV and IV Bus fault levels and contribution of fault current by each ICT for HV and IV bus fault is as shown in the following table
Calculate HV and IV CT Primary Currents for fault at respective side LA
**FOR ICT-**.
(NOTE: Relay current corresponding to 70% of these calculated current values to be used for setting of ICT Backup Relay HS element. )
HV and IV Bus fault levels and contribution of fault current by each ICT for HV and IV bus fault is as shown in the following table
Calculate HV and IV CT Primary Currents for fault at respective side LA
**FOR ICT-**.
Bus Fault Levels MVA | ||
Bus | Fault Type | Fault Level in MVA |
ICT HV Bus | 3-Phase (LLL) | |
1-Phase (SLG) | ||
ICT IV Bus | 3-Phase (LLL) | |
1-Phase (SLG) |
Fault Current contribution by ICTs | ||||
Fault At | Type | ICT | Winding | Ampere |
ICT HV Bus Fault | 3-Phase (LLL) | ICT-I | HV Winding | |
IV Winding | ||||
ICT-II | HV Winding | |||
IV Winding | ||||
1-Phase (SLG) | ICT-I | HV Winding | ||
IV Winding | ||||
ICT-II | HV Winding | |||
IV Winding | ||||
ICT IV Bus Fault | 3-Phase (LLL) | ICT-I | HV Winding | |
IV Winding | ||||
ICT-II | HV Winding | |||
IV Winding | ||||
1-Phase (SLG) | ICT-I | HV Winding | ||
IV Winding | ||||
ICT-II | HV Winding | |||
IV Winding |
(NOTE: Relay current corresponding to 70% of these calculated current values to be used for setting of ICT Backup Relay HS element. )
1.a) HV Side LA 3-Ph fault current =
Amp.
1.b) Current contribution by ICT for above fault = Amp.
1.c) Current contribution from HV Bus for above fault = Amp.
2.a) HV Side LA 1-Ph fault current =
Amp.
2.b) Current contribution by ICT for above fault = Amp.
2.c) Current contribution from HV Bus for above fault = Amp.
3.a) IV Side LA 3-Ph fault current =
Amp.
3.b) Current contribution by ICT for above fault = Amp.
3.c) Current contribution from IV Bus for above fault = Amp.
SNa) IV Side LA 1-Ph fault current =
Amp.
SNb) Current contribution by ICT for above fault = Amp.
SNc) Current contribution from IV Bus for above fault = Amp.
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