Rf3 - Calculations of current for setting of ICT backup relay Highset Element

OcEf Calc Grid ICT
     At a 220/132kV Sub-Station there are two ICTs operating in parallel. ICT-I having capacity of 200 MVA. Whereas the capacity of ICT-II is 100 MVA.



     HV and IV Bus fault levels and contribution of fault current by each ICT for HV and IV bus fault is as shown in the following table

     Calculate HV and IV CT Primary Currents for fault at respective side LA
**FOR ICT-**.

Bus Fault Levels MVA
Bus Fault Type Fault Level in MVA
ICT HV Bus 3-Phase (LLL)
1-Phase (SLG)
ICT IV Bus 3-Phase (LLL)
1-Phase (SLG)


Fault Current contribution by ICTs
Fault At Type ICT Winding Ampere
ICT HV Bus Fault 3-Phase (LLL) ICT-I HV Winding
IV Winding
ICT-II HV Winding
IV Winding
1-Phase (SLG) ICT-I HV Winding
IV Winding
ICT-II HV Winding
IV Winding
ICT IV Bus Fault 3-Phase (LLL) ICT-I HV Winding
IV Winding
ICT-II HV Winding
IV Winding
1-Phase (SLG) ICT-I HV Winding
IV Winding
ICT-II HV Winding
IV Winding


(NOTE: Relay current corresponding to 70% of these calculated current values to be used for setting of ICT Backup Relay HS element. )
1.a) HV Side LA 3-Ph fault current =    Amp.

1.b) Current contribution by ICT for above fault =    Amp.

1.c) Current contribution from HV Bus for above fault =    Amp.

2.a) HV Side LA 1-Ph fault current =    Amp.

2.b) Current contribution by ICT for above fault =    Amp.

2.c) Current contribution from HV Bus for above fault =    Amp.

3.a) IV Side LA 3-Ph fault current =    Amp.

3.b) Current contribution by ICT for above fault =    Amp.

3.c) Current contribution from IV Bus for above fault =    Amp.

SNa) IV Side LA 1-Ph fault current =    Amp.

SNb) Current contribution by ICT for above fault =    Amp.

SNc) Current contribution from IV Bus for above fault =    Amp.

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