Problem
Consider a S/S having
one transformers of 132/33kV 25 MVA having leakage reactance of 9.5%. Let the
S/S source impedance be negligible as compared to transformer leakage
reactance. Find out the 3-phase and 1-phase fault current for 33kV Bus fault.
Solution
3-Ph short circuit MVA
= 25x100/9.5 = 263 MVA ---- ( using
formula – 3)
1-Ph short circuit MVA
= 3x25x100/(9.5+9.5+9.5) = 263 MVA - (
using formula – 4)
(As for transformer X1
= X2 = X0)
For 33kV voltage 1 MVA
= 17.5 Amp
Hence this current will
be 17.5*263 = 4602 Amp.
Comments
In actual practice
source impedance is not negligible hence 3-Ph fault MVA will be less than this.
It shall be a good approximation to consider it as 80% of calculated value.
Hence 3-phase fault current shall be 0.8*4602 ≈ 3500 Amp. (and 1-phase fault
current too)
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