Consider a S/S having two transformers of 132/33kV operating in parallel. one transformer of 25 MVA having leakage reactance of .
and other transformer of 50 MVA having leakage reactance of . Let the S/S source impedance be negligible as compared to transformer leakage reactance.
Find out the 3-phase fault current for 33kV Bus fault.
(Note: Consider Base MVA as 100).
Impedance of 50 MVA transformer to base of 100 MVA (XT1)
%
Impedance of 25 MVA transformer to base of 100 MVA (XT2) %
Impedance of 25 MVA transformer to base of 100 MVA (XT2) %
Equivalent impedance between source and fault point will be XT1||XT2
%
Using the formula for 3-Ph short circuit MVA = BaseMVA*100/X1, 3-Ph short circuit MVA at 33kV bus will be
MVA
Converting 3-Ph fault MVA to equivalent current at 33kV we get 3-Ph fault current as
Amp.
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